1. Write an equation for a line that has a slope of 4 and passes through the point (-4, 7).
a) y = 4x + 23
b) y = 4x + 10
c) y = 4x + 17
d) y = 4x - 11
Please help I beg you

y = 4x+23

Step-by-step explanation:

The slope intercept form of a line is

y = mx+b where m is the slope and b is the y intercept

y = 4x+b

Substitute the point into the equation

7 = 4(-4)+b

7 = -16+b

Add 16 to each side

7+16 = b

23 = b

y = 4x+23

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

yes the total will be same because in both of them the expression.is rearranged but their sign remains the same hence it hss just been shuffled