Given that a child spends at least 1 hour per day outside, what is the probability, rounded to the nearest hundredth if necessary, that the child spends less than 1 hour per day on electronics? 0.22 0.25 0.70 0.88

0.88

Step-by-step explanation:

We would consider the first case second column

So 14/16 will be the probability that comes out be approximately 0.88.

hi sorry I've been gone for so long I forgot about until today so

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

i dont know if you cant find a way its best to actually add all of them start from 105 tho

step-by-step explanation: