Write the equation of the line that has a slope of 2 and passes through the point (-5, 1). y = 2x - 5

y = 2x + 11

y = 2x + 1

y = 2x + 9

Step-by-step explanation:

= 2x +b

Use the given point (2, 5)

5 = 2(2) +b

b = 5 -4 = 1

The equation of the line is

y = 2x +1

Note general form of the slope-intercept form of a line is y = mx +b, where m is the slope and b is the y-axis intercept

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.