Solve for the missing values in the table below: ​

The answers to your questions are given below.

Step-by-step explanation:

A. Determination of the length.

Length (cm) = 32

Length (m) =?

Length (mm) =?

I. Determination of the length in m.

100 cm = 1 m

Therefore,

32 cm = 32 × 1 m / 100 cm

32 cm = 0.32 m

II. Determination of the length in mm

1 cm = 10 mm

Therefore,

32 cm = 32 cm × 10 mm / 1 cm

32 cm = 320 mm

B. Determination of the height.

Height (m) = 1.58 m

Height (cm) =?

Height (mm) =?

I. Determination of the height in cm.

1 m = 100 cm

Therefore,

1.58 m = 1.58 m × 100 cm / 1 m

1.58 m = 158 cm

II. Determination of the height in mm

1 m = 1000 mm

Therefore,

1.58 m = 1.58 m × 1000 mm / 1 m

1.58 m = 1580 mm

C. Determination of the width.

Width (mm) = 36 mm

Width (m) =?

Width (cm) =?

I. Determination of the width in m.

1000 mm = 1 m

Therefore,

36 mm = 36 mm × 1 m / 1000 mm

36 mm = 0.036 m

II. Determination of the width in cm

10 mm = 1 cm

Therefore,

36 mm = 36 mm × 1 cm / 10 mm

36 mm = 3.6 cm

D. Determination of the length.

Width (mm) = 105 mm

Width (m) =?

Width (cm) =?

I. Determination of the width in m.

1000 mm = 1 m

Therefore,

105 mm = 105 mm × 1 m / 1000 mm

105 mm = 0.105 m

II. Determination of the width in cm

10 mm = 1 cm

Therefore,

105 mm = 105 mm × 1 cm / 10 mm

105 mm = 10.5 cm

E. Determination of the length.

Length (m) = 2 m

Length (cm) =?

Length (mm) =?

I. Determination of the length in cm.

1 m = 100 cm

Therefore,

2 m = 2 m × 100 cm / 1 m

2 m = 200 cm

II. Determination of the length in mm

1 m = 1000 mm

Therefore,

2 m = 2 m × 1000 mm / 1 m

2 m = 2000 mm

Summary:

Item >>>>>>>> m >>>> cm >>>> mm

A. Lenght >>> 0.32 >> 32 >>>> 320

B. Height >>> 1.58 >> 158 >>>> 1580

C. Width >>> 0.036 >> 3.6 >>>> 36

D. Length >> 0.105 >> 10.5 >>> 105

E. Width >>> 2 >>>>>> 200 >>> 2000

30 units^2

step-by-step explanation:

area is l × w

the length is 3

and the width is 10

3 × 10= 30 units squared

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm