A basketball free throw can be modeled by a parabolic path, which can be represented by the function b(x) = - 0.25 x^2 + 4x, where x is time, in seconds, and b(x) is the height of the ball off the ground in feet. What is the VERTEX and what do the coordinates mean in the context of the problem?

please solve algebraically

The vertex of this problem is (8,16). This means that the highest height the ball reaches is at t = 8s, and this maximum height is of 16 feet.

Step-by-step explanation:

Vertex of a quadratic function:

Suppose we have a quadratic function in the following format:

It's vertex is the point

In which

Where

If a<0, the vertex is a maximum point, that is, the maximum value happens at , and it's value is .

b(x) = - 0.25 x^2 + 4x

Quadratic equation with .

Vertex:

The vertex of this problem is (8,16). This means that the highest height the ball reaches is at t = 8s, and this maximum height is of 16 feet.

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)