What is the slope of the line whose equation is y-4=5/2(x-2)? ​

5/2

Step-by-step explanation:

We know,

Equation of the slope is, y = mx + c.   Where m is the slope.

y - 4 = 5/2*(x-2)

y = 5/2*(x-2) + 4

y = (5/2)x - 5 + 4

y = (5/2)x - 1

y = (5/2)x + (-1)      [y = mx + c form]

Slope, m = 5/2

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Simplify 52⋅(x−2)52⋅(x-2). Apply the distributive property. y−4=5/2x+5/2⋅−2 Combine 5252 and x

y−4=5x2+5/2⋅−2 Cancel the common factor of 2.Factor 2 out of −2

y−4=5x2+52⋅(2(−1))y-4=5x2+52⋅(2(-1))

Cancel the common factor.

y−4=5x2+52⋅(2⋅−1)y-4=5x2+52⋅(2⋅-1)

Rewrite the expression.

y−4=5x2+5⋅−1y-4=5x2+5⋅-1

Multiply 55 by −1-1.

y−4=5x2−5

Add 44 to both sides of the equation.

y=5x2−5+4y=5x2-5+4

Add −5-5 and 44.

y=5x2−1

Reorder terms.

y=52x−1

THE ANSWER IS M = 5/2

the image of (6, 9) under a dilation is (4, 6). the scale factor is

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.