Two six-sided fair dice are rolled. The probability that at least one number is odd and the sum of the two numbers is even is
v . The probability that exactly one
number is 6 and the product of the two numbers is at most 15 is

Step-by-step explanation:

There are 36 equally likely pairs: (1,1);(1,2);(1,3),…(6,4);(6,5);(6,6). The corresponding sums: 2,3,4,….10,11,12. are best observed with an addition table for 1-6 with 1-6. 3 is simple enough because only (1,2) and (2,1) can sum to 3. So P= 2/36 = 1/18. P(SUM =4) = 3/36 because (1,3);(2,2);(3,1) are the only pairs that sum to 4. The best way to see this is look at the first die. To get a sum of 4, the first die must be 1,2 or 3. Each of those first rolls forces one outcome for the second die. P(10) = 3/36 because the first die must be 4,5,or6.

b: |12 – x| ≤ 0.25

step-by-step explanation:      

let x be the possible lengths in inches, of the ribbons jaime cut.

we have been given that jaime is cutting strips of ribbon for a project. he tries to cut each piece to be 12 inches long, but sometimes he cuts it too long or too short by as much as 0.25 inch.  

we can represent this information in an inequality as:

by the definition of absolute value function we will get,

upon combining our inequalities we will get,

therefore, the inequality   describes all the possible lengths (x), in inches, of the ribbons jaime cut.

step-by-step explanation: