What is the degree of the simplest polynomial with integer coefficients that has √2 , 2 , √2 + i , and 2 + 2i as some of its zeros? a. 6
b. 7
c. 8
d. 9

If the polynomial has integer coefficients, then any complex roots with non-zero imaginary part must occur along with their conjugates. If a + bi is a root, then so is a - bi.

The given polynomial would then have at least 6 roots: √2, 2, √2 + i and √2 - i, and 2 + 2i and 2 - 2i. So the minimum degree is (A) 6.

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation: