Please help! urgently

sinC =

Step-by-step explanation:

We require to find the side DE before finding sinC

Using Pythagoras' identity in the right triangle

DE² + CE² = CD²

DE² + 5² = ( )²

DE² + 25 = 41 ( subtract 25 from both sides )

DE² = 16 ( take the square root of both sides )

DE = = 4 , then

sinC = = = , rationalise the denominator

sinC = × =

step-by-step explanation:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.