Exhibit 11-3 The contents of a sample of 26 cans of apple juice showed a standard deviation of 0.06 ounce. We are interested in testing to determine whether the variance of the population is significantly more than .003. The null hypothesis . a. should not be rejected b. should be rejected c. should be revised d. None of these answers are correct.

a. should not be rejected

Step-by-step explanation:

H0 : σ² = 0.003

H1 : σ² > 0.003

We obtain the test statistic :

χ² = [(n - 1) * s²] ÷ σ²

s = sample standard deviation = 0.06

n = sample size = 26

σ² = 0.003

χ² = [(26 - 1) * 0.06²] ÷ 0.003

χ² = (25 * 0.06²) / 0.003

χ² = 30

Using the Pvalue from χ² calculator :

Pvalue = 0.2242

Using α = 0.05

Pvalue > α; we fail to reject the Null

answer: the first graph

step-by-step explanation:

the answer would be 484

step-by-step explanation:

just multiply 0.484 times 1,000 (formula)