A large restaurant chain wanted to determine if its employees were taking sick days on some days of the week more than others. They took a random sample of 140 sick days taken and recorded the day of the week for each sick day. Here are the results: Day Mon Tue Wed Thu Fri Sat Sun # of sick days 22 11 16 17 21 28 25 They want to perform a x? goodness-of-fit test to determine if these results suggest that employees were more likely to take sick days on certain days. What is the expected count of sick days taken on Saturday? You may round your answer to the nearest hundredth. Expected:

0.2

Step-by-step explanation:

Given the data :

Day : Mon Tue Wed Thu Fri Sat Sun

# of sick days 22 11 16 17 21 28 25

The expected count of sick days taken on Saturday is obtained thus :

Expected count = (row total * column total) / overall total

Here, the table is just one way :

Hence, we use :

Observed value / total days

Hence,

Expected count on Saturday = sick days on Saturday / total sick days

Expected count on Saturday = 28 / (22+11+16+17+21+28+25)

Expected count on Saturday = 28 / 140

= 0.2

b, 20 yards

step-by-step explanation:

tell you what. i'll find the length of the medians and you can fill in the blanks where they belong.

br

b = (2a,0)

r = (a/2,b/2) remember these things are medians. they go to the 1/2 way point of the line opposite the vertex they face.

br^2 =   (2a - a/2)^2 + (0 - b/2)^2

br^2 = (3/2 a) ^2 + b^2 / 4

br^2 = 9/4 a^2 + b^2 / 4   we need to find some relationship between a and b.

let's try ab = bc  

ab = 2a

bc = (2a - a)^2 + (b - 0)^2

bc = sqrt(a^2 + b^2)

ab = bc

2a = sqrt(a^2 + b^2) square both sides.

4a^2 = a^2 + b^2 subtract a^2 from both sides.

sqrt(3a^2) = sqrt(b^2)

sqrt(3)a = b

let's put b into br^2

br^2 = 9/4 a^2 + 3b^2 / 4

br^2 = 12 a^2 / 4

br^2 = 3a^2 

br = sqrt(3) * a

cp

c = (a,b) ; p = (a,0) this is another application of the distance formula, and it is a good one.

cp^2 = (a - a)^2 + (b - 0)^2

cp^2 = 0 + b^2

cp^2 = b^2 which you can see from the diagram. 

cp = sqrt(b^2)

cp = b but b = sqrt(3) * a 

cp = sqrt(3)*a

aq

a = (0,0)

q = (3/2) a, b/2

aq^2 = (3a/2 -0)^2 + (b/2 - 0)^2

aq^2 = 9a^2/4 + b^2/4

but b = sqrt(3) * a 

aq^2 = 9a^2 / 4 + (sqrt(3)*a)^2 /4

aq^2 = 9 a^2/ 4 + 3 a^2 / 4

aq^2 = 12 a^2/4

aq^2 = 3 a^2

aq = (sqrt  3) * a which agrees with the other two.