Assume that college students have IQ scores that are normally distributed with a mean of 100 and a standard deviation of 15. Find the probability that a randomly selected college student has an IQ greater than 115.5. Group of answer choices

0.018 is  the probability that a randomly selected college student has an IQ greater than 131.5                                

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 100

Standard Deviation, σ = 15

We are given that the distribution of IQ score is a bell shaped distribution that is a normal distribution.

Formula:

a) P(IQ greater than 131.5)

P(x > 131.5)

Calculation the value from standard normal z table, we have,  

0.018 is  the probability that a randomly selected adult has an IQ greater than 131.5

answer

false

explanation

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d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it