Figure 3 Q.4 Determine the largest allowable square cross section of a steel shaft of length 6 m if the maximum
shearing stress is not to exceed 120 MPa when the shaft is twisted through one complete revolution. Use
G=77.2GPA.

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2

35x 3= 105

step-by-step explanation:

35+35= 70   70 + 35= 105

step-by-step explanation: