Solve i + j + t (3i - j) = -i + s (j)
In the context of Vector Equations of a Line

r = i + j + (-2/3)(3i - j)

Step-by-step explanation:

Vector Equation of a line - r = a + kb ; where r is the resultant vector of adding vector a and vector b and k is a constant

if a = i + j ; b = t(3i - j) and r = -i +s(j)

for this to be true all the vector components must be equal

summing i 's

i + 3ti  = -i; then t = -2/3

j - tj = sj; then s = 1-t; substitue t; s=1+2/3 = 5/3

so r = i + j + (-2/3)(3i - j) which will symplify to -i + 5/3j

hello from mrbilldoesmath!

answer:

a(n) - a(n-1) -3

discussion:

this ones a bit interesting. given a(n) = 5 - 3n consider this:

a(n-1) = 5 - 3(n-1)

          = (5 - 3n) + 3             => but a(n) = 5 - 3n, the first term

          = a(n)   + 3                 => subtract 3 from both sides

a(n-1) -3 = a(n)  

or

a(n) - a(n-1) -3

you,

mrb

the answer is 844

step-by-step explanation:

it is 844 because if you add 836.50 + 7.5 you will get 844