Help me moderate helping me​

Problem 1

It's not clear if the person deposits at the start of the quarter, or at the end of the quarter. I'm going to assume they deposit at the end of the quarter. This means we go with an ordinary future value of annuity.

The formula we use is

F = P*( (1+i)^n - 1)/i

where,

In this case,

So,

F = P*( (1+i)^n - 1)/i

300,000 = P*( (1+0.02)^100 - 1)/0.02

300,000 = P*(312.232305912618)

P = (300,000)/(312.232305912618)

P = 960.823061288088

P = 960.82

You must deposit $960.82 per quarter

If you deposit that amount of money per quarter, for 100 quarters, then you deposited a total of 960.82*100 = 96,082 dollars in total.

The amount of interest is 300,000 - 96,082 = 203,918 dollars

Problem 2

We use the same formula from problem 1. This time we know the periodic payment ($250 per month) and we want to find the value of F

More specifically, we have this given info:

So,

F = P*( (1+i)^n - 1)/i

F = 250*( (1+0.006)^360 - 1)/0.006

F = 317,306.360545277

F = 317,306.36

If you deposit $250 per month, for 360 months, then you'll have $317,306.36 in the account.

This includes interest. The total amount deposited, without interest involved, is 250*360 = 90,000 dollars.

Therefore, the amount of interest earned is 317,306.36 - 90,000 = 227,306.36 dollars.

the terms of a geometric sequence can be found by beginning with the first term and multiplying by the common ratio repeatedly. a recursive formula for a geometric sequence with common ratio r is given by an=ran−1 a n = r a n − 1 for n≥2 n ≥ 2 .

step-by-step explanation: