Complete the square of the quadratic equation x^2 - 2x - 35 = 0. What is the vertex of the equation? ( )( )

Step-by-step explanation:

x^2 - 2x - 35 = 0

Solve for x over the real numbers:

x^2 - 2 x - 35 = 0

Add 35 to both sides:

x^2 - 2 x = 35

Add 1 to both sides:

x^2 - 2 x + 1 = 36

Write the left hand side as a square:

(x - 1)^2 = 36

Take the square root of both sides:

x - 1 = 6 or x - 1 = -6

Add 1 to both sides:

x = 7 or x - 1 = -6

Add 1 to both sides:

 x = 7 or x = -5  as for the vertex plane curve | Cartesian equation x^2 - 2 x - 35 = 0 | vertex (not a possible affine variety)

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).