Simplify the polynomial (4n2 + 3n - 5) - (2n2 + 3n+ 6)

2n^2 - 11

steep by steep explanation

=(4n^2 + 3n -5) -(2n^2 + 3n +6)

= 4n^2 +3n -5 - 2n^2 - 3n -6

= 2n^ - 11

We keep brackets

(4n^2 + 3n - 5 ) -  (2n^2 + 3n + 6)

We change signs and we group

4n^2 - 2n^2 + 3n - 3n - 5-6

We simplify

2m^2 - 11

= 2.n^2  - 11

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐