The area of cross section of the large piston in a hydraulic machine is 1m² and that of small piston is 0.5m².calculate the force that must be applied on the small piston to lift a load of 1000N on the large piston

The force that must be applied on the small piston has a magnitude of 500 newtons.

Step-by-step explanation:

By Pascal's Principle, we know that pressure within any point of a closed hydraulic system is the same. Hence, the hydraulic machine can be described by the following model:

(1)

Where:

- Forces applied on the small and large pistons, in newtons.

- Areas of the small and large pistons, in square meters.

If we know that , and , then the force to be applied on the small piston is:

The force that must be applied on the small piston has a magnitude of 500 newtons.

the 3rd option is right

step-by-step explanation:

welll its a very hard question but ill

step-by-step explanation:

first you take the 6 dollars and add 10 to it then add the 50 to that then multiply by 8 with xy and your answer will be

hope this