i will mark brainliest, thank, and 5star Find the smallest positive value of the nonnegative number \lambdaλ such that the inequality
\frac{a+b}{2}\ge \lambda \sqrt{ab}+(1-\lambda) \sqrt{\frac{a^2+b^2}{2}}
2
a+b
​
≥λ
ab
​
+(1−λ)
2
a
2
+b
2

​

​

holds for all positive real numbers a, ba, b.

b. the decimal could be two-tenths.

step-by-step explanation:

the correct answer is b) histograms can be used to exhibit the shape of distributions. this is because histograms count the frequency of each possible answer, so one is able to see which results are more common and which are less common.

its d. the first coordintaes are 10,32

step-by-step explanation: