During the first 13 weeks of the television season, the Saturday evening 8:00 p. m. to 9:00 p. m. audience proportions were recorded as ABC 30%, CBS 27%, NBC 26%, and independents 17%. A sample of 300 homes two weeks after a Saturday night schedule revision yielded the following viewing audience data: ABC 96 homes, CBS 69 homes, NBC 90 homes, and independents 45 homes. Test with α = 0.05 to determine whether the viewing audience proportions changed. State the null and alternative hypotheses. H0: pABC ≠ 0.30, pCBS ≠ 0.27, pNBC ≠ 0.26, pIND ≠ 0.17Ha: pABC = 0.30, pCBS = 0.27, pNBC = 0.26, pIND = 0.17 H0: pABC = 0.30, pCBS = 0.27, pNBC = 0.26, pIND = 0.17Ha: pABC ≠ 0.30, pCBS ≠ 0.27, pNBC ≠ 0.26, pIND ≠ 0.17 H0: The proportions are not pABC = 0.30, pCBS = 0.27, pNBC = 0.26, pIND = 0.17.Ha: pABC = 0.30, pCBS = 0.27, pNBC = 0.26, pIND = 0.17 H0: pABC = 0.30, pCBS = 0.27, pNBC = 0.26, pIND = 0.17Ha: The proportions are not pABC = 0.30, pCBS = 0.27, pNBC = 0.26, pIND = 0.17.Find the value of the test statistic. (Round your answer to three decimal places.)Find the p-value. (Round your answer to four decimal places.)p-value =State your conclusion. Reject H0. There has been a significant change in the viewing audience proportions. Reject H0. There has not been a significant change in the viewing audience proportions. Do not reject H0. There has been a significant change in the viewing audience proportions. Do not reject H0. There has not been a significant change in the viewing audience proportions.

Part 1: Do not reject H0. There has not been a significant change in the viewing audience proportions.(The above conclusion holds as the p-value is greater than the significance level of 0.05)

Part 2:

H0:  

Ha:  

Part 3: The test statistic is given as 3.0081.

Part 4: The p-value is given as  0.39037

Step-by-step explanation:

As per the data

Part 2

H0:  

Ha:  

Part 3

As per the sample is of 300 homes, the expected values are given as

ABC=p(ABC)*300=0.30*300=90

CBS=p(CBS)*300=0.27*300=81

NBC=p(NBC)*300=0.26*300=78

IND=p(IND)*300=0.17*300=51

Now the values actually are given as

ABC=94

CBS=71

NBC=88

IND=47

So the test static is given as

So the test statistic is given as 3.0081.

Part 4

Now the degree of freedoms are given as 4-1=3

and chi square  is given as 3.0081 so for α = 0.05 , the p-value is given as  0.39037

Part 5.

As the value of p in part 4 is greater than the value of α = 0.05, thus Do not reject H0. There has not been a significant change in the viewing audience proportions.(The above conclusion holds as the p-value is greater than the significance level of 0.05)

Step-by-step explanation:

yes

$25

step-by-step explanation:

25 - 4.50 = 20.5

20.5 / 2 = 10.25

10.25 + 10 = 20.25

20.25 - 12.50 = 7.75

therefore the answer is $25 as shown as the first number.

the multiples of 15 are 15, 30,45, 60, 75, 90, 105, 120, 135, 150, 165, 180, 195,   210, 225, 240, 255, 270, 285, 300, 315, 330, 345, 360, 375,   390, 405, 420, 435, 450, 465, 480, 495, 510, 525, 540, 555, 570, 585, 600, 615, 630, 645, 660, 675, 690, 705, 720, and 735.

the factors of 15 are 1, 3, 5, and 15.

hope that , fam!

-une, your fren : )