Gravel is being dumped from a conveyor belt at a rate of 40 ft3/min, and its coarseness is such that it forms a pile in the shape of a cone whose base diameter and height are always equal. How fast is the height of the pile increasing when the pile is 11 ft high? (Round your answer to two decimal places.)

0.42ft/mn

Step-by-step explanation:

we have the following information to answer this question

dv/dt = 40 feet

height = 11 ft

volume = 1/3πr²h

= 1/3π(h/2)²h

= 1/3πh³/4

= πh³/12

dv/dt = π3h²/12

= πh²/4

dh/dt = 4/πh²dv/dt

= 4(40)÷22/7(11)²

= 160/380.29

= 0.42 ft/min

The height of the pile is therefore increasing by 0.42ft/min at a height of 11 feets

total amount to be paid = $19.5

step-by-step explanation:

given ,

original price = $25.99

discount = 25%

discount amount = 25% of original price

discount amount = 25/100   * 25.99

discount amount = $6.49

hence , the total amount to be paid = original price - discount amount

                                                            = $25.99 - $6.49

                                                            =$19.5

total amount to be paid = $19.5

i only know the sequence of arithmetic it adds the first is 5+4 then it goes up as it adds to then it is 9+5 then 14+6 then to 20+7 and so on. 5,9,14,20,27,35.

step-by-step explanation: