What is the orientation of =22+4−30 y=2x^2+4x−30? That is, does it open upward or open downward? How could you change the equation to make the graph open the opposite way?

What is the stretch factor of =22+4−30
y=2x^2+4x−30? Justify your answer.

Can you identify the vertex of =22+4−30
y=2x^2+4x−30
by looking at the equation? If not, talk with your team about strategies you could use to find the vertex without using a table or graphing calculator and then apply your new strategy to the problem. If your team is stuck consider doing parts (i) through (iii) below.

What are the
x
-intercepts of the parabola?

Where is the vertex located in relation to the
x
-intercepts? Can you use this relationship to find the
x
coordinate of the vertex?

Use the
x
-coordinate of the vertex to find its
y
-coordinate.

Make a quick sketch of =22+4−30
y=2x^2+4x−30
and write its equation in graphing form.