A rectangle has horizontal sides of 3(x-2)ft and vertical sides of 4x-7+(-2x)ft. Find the value of x so that the rectangle of x has a perimeter of 34 ft.

x = 6

Step-by-step explanation:

Perimeter of the rectangle = 34 ft

Length of the rectangle = 3(x-2) ft

Width of the rectangle = 4x-7+(-2x) ft

= 4x - 7 - 2x

= 2x - 7 ft

Perimeter of a rectangle = 2(length + width)

34 = 2{3(x-2) + 2x - 7 }

34 = 2{3x - 6 + (2x - 7)}

34 = 2(3x - 6 + 2x - 7)

34 = 2(5x - 13)

34 = 10x - 26

34 + 26 = 10x

60 = 10x

x = 60/10

x = 6

Length of the rectangle = 3(x-2) ft

= 3(6 - 2)

= 3(4)

= 12 ft

Width of the rectangle = 2x - 7 ft

= 2(6) - 7

= 12 - 7

= 5 ft

answer: okw

step-by-step explanation: