The probability of spinning an odd number, flipping heads and then spinning a 3 is?

Work Shown:

A = probability of landing on an odd number

A = 5/9 because there are 5 odd numbers out of 9 total

B = probability of getting heads

B = 1/2

C = landing on 3 on the spinner

C = 1/9

Multiply the values of A,B,C

A*B*C = (5/9)*(1/2)*(1/9) = (5*1*1)/(9*2*9) = 5/162

Note: The fraction 5/162 converts to the approximate decimal 0.03086 which then converts to 3.086%, when rounding to the nearest tenth of a percent we get 3.1%

-10i^2-4i

step-by-step explanation:

evaluate for p=2,q=5i

(2−4)(2+5i)i

(2−4)(2+5i)i

=−10i2−4i