The length of a rectangle is 4 yd longer than its width. If the perimeter of the rectangle is 56 yd, find its length and width.

The length of the rectangle is 16 yards and the width is 12 yards.

Step-by-step explanation:

The length is 4 yds longer than the width. Let's remove that from the perimeter so that the perimeter will be as if all sides had the same length (remember there are 2 sides for length and 2 sides for width).

Now we made it so that the extra 4 yards are gone and all sides are equal like a square. Now we can divide by 4 to determine the length of each of the now equal sides

So all of the sides are 12, 12, 12, and 12. To two of the sides we can add back the extra 4 yards we took out giving us sides of 12, 12, 16, and 16.

Let's add it all together and see if it makes the perimeter of 56

It does! Since the length is 4 yds longer than the width the length is 16 and width is 12.

answer: answer is c!

ok i got to organize the

3/15 and 12/55

3*

aha

3*4 equals 12 but not

a: no

b:

8/24 12/35

no

gautie

it's c

5/18 = 25/90

5*5=25

18*5 = 90

hope that you!

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step-by-step explanation: