Mathematics, 23.06.2021 21:50 kelonmazon2492

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Answer from: 911782

(a) $a+b-c\\-2+-3-4\\-5-4\\-9$

(b) $b+c^3\\-3+4^3\\-3+64\\61$

(c) $\frac{3b^2-c^2+a^2}{-3abc} \\\frac{3(-3)^2-(4)^2+(-2)^2}{-3(-2)(-3)(4)} \\\frac{3(9)-16+4}{6(-3)(4)} \\\frac{27-16+4}{-18(4)} \\\frac{11+4}{-72} \\\frac{15}{-72} \\-\frac{5}{24}$

Answer from: jillericamurph46

The answer to (A) is -9.

The answer to (B) is 61.

The answer to (C) is $-\frac{5}{24}$ in fraction form or -0.208 in decimal form.

Step-by-step explanation:

For problem (A), which is a+b-c , in order to solve for this problem, plug in the information given from the question. The problem will look like (-2)+(-3)-(4) . Solve the problem by first adding (-2) + (-3), which equals (-5), and then, solve for (-5) -(4), which equals -9. The final answer for problem (A) will be -9.

For problem (B), which is $b+c^{3}$ , start by plugging in the information given from the question. The problem will look like $(-3)+(4)^{3}$ . Solve the problem by cubing 4, which equals 64, and then, solve for (-3)+(64), which equals 61. The final answer for problem (B) will be 61.

For problem (C), which is $\frac{3b^{2}-c^{2}+a^{2} }{-3abc}$ , start by plugging in the information given from the question. The problem will look like $\frac{3(-3)^{2}-(4)^{2}+(-2)^{2} }{-3(-2)(-3)(4)}$ . Solve the problem by first simplifying the numerator.

To simplify the numerator, raise -3 to the power of 2, which will equal 9, and multiplying 3 by 9, which will look like $\frac{27-(4)^{2}+(-2)^{2} }{-3(-2)(-3)(4)}$ . Next, raise 4 to the power of 2, which equals 16, and multiply -1 by 16, which will look like $\frac{27-16+(-2)^{2} }{-3(-2)(-3)(4)}$ . The next step is to raise -2 to the power of 2, which will look like $\frac{27-16+4 }{-3(-2)(-3)(4)}$ . Then, subtract 16 from 27, which equals 11, and add (11) + (4), which equals 15. The numerator equals 15.

Next, simplify the denominator. First, multiply -3 by -2, which equals 6, and the problem will look like $\frac{27-16+4 }{6(-3)(4)}$ . Then, multiply 6 by -3, which equals -18, and the problem will look like $\frac{27-16+4 }{-18(4)}$ . The next step is to multiply -18 by 4, which equals -72, and the denominator will equal -72.

Then, reduce the expression by cancelling the common factor, and the common factor is 3. The final answer will be $-\frac{5}{24}$ in fraction form or -0.208 in decimal form.

Answer from: Quest

three-fourths of an hour

36÷48=0.75

0.75= $\frac{3}{4}$

Answer from: Quest

Sis less than or equal to 75 (bottom left)

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