Do the side lengths 7, 20 and 21 form a right triangle?

Work Shown:

a^2+b^2 = c^2

7^2+20^2 = 21^2

49+400 = 441

449 = 441

We end up with a false equation, so the original equation is false for those a,b,c values.

By the pythagorean theorem converse, we do not have a right triangle.

Because a^2+b^2 > c^2, this triangle is acute.

answer: b)

step-by-step explanation:

its a dot plot because since the score is not high numbers.

- r3ktforgood ☕