A certain quadratic function has x-intercepts at 2 and 3. What are the x-coordinates of its vertex? a)7/2
b)1/2
c)3/2
d)5/2

D

Step-by-step explanation:

The equation is going to by

y = (x - 2)(x - 3)         Multiply to remove the brackets.

y = x^2 - 2x - 3x + 6

y = x^2 - 5x + 6       Now what you are going to do is complete the square.

y = (x^2 - 5x  +  __ ) +6

Take - 5

Divide it by 2 = -5 / 2

and square it = (-5 / 2)^2 = 25/4

Put this result inside the brackets.

y = (x^2 - 5x + 25/4 ) + 6               Now subtract 25/4 after the 6

y = (x^2 - 5x + 25/4) + 6 - 25/4

y = (x - 5/2)^2 - 1/4

The x coordinate of the vertex  is 5/2

You could also do this by using x = -b/2a = - -5/2*1 = 5/2

idk

step-by-step explanation:

pentagon

step-by-step explanation:

the coordinates   a(5, -2), b(3,-1),c(-4,-4) d(-3,8) and e(-1,4) forms the vertices of the polygon when they are connected in order.

in order to classify that which polygon is it with the given coordinates, first count the number of vertices and then count the number of sides it can make with these vertices.

since, the given coordinates have five vertices, therefore, it will make five sides. moreover, pentagon is regular in nature therefore it will be convex.

now, a polygon with five sides is known as pentagon, therefore, the given polygon is the pentagon.