Suppose you know a certain parabola has a vertex of (2, 1) and a y-intercept of 4. By symmetry, you can conclude that the parabola contains which of the following points? a) (4,4)
b) (-2,4)
c) (-2,1)
d) (4,1)

A

Step-by-step explanation:

We are given a parabola with a vertex point of (2, 1) and a y-intercept of y = 4.

And we want to determine another point on the parabola.

Recall that a parabola is symmetric along the axis of symmetry, which is the x-coordinate of the vertex.

Note that since the y-intercept of the parabola is y = 4, this means that a point on our parabola is (0, 4).

To get from (2, 1) to (0, 4), we move two units left and three units up.

Since the parabola is symmetric along axis of symmetry, another point on the parabola will be two units right and three units up. This yields (2 + 2, 1 + 3) or (4, 4).

Our answer is A.

i'm pretty sure it's 477,585,296, but perhaps my math is incorrect.

75 tickets have been sold so far.

step-by-step explanation:

in this question it is clearly mentioned that 45 children's tickets have been sold and this number is 60% of the total tickets sold.

now let's assume the total number of tickets sold be x.

then 60% of x = 45

⇒

⇒ x(.6) = 45

by dividing with .6 on both the sides of the equation

⇒ x = 75

therefore 75 tickets have been sold so far.