The midpoint of a line segment from P1 to P2 is (-5,2). If P1 = (-1,7), what is P2?

Hope it helps you!

-miraculousfanx-

p2 = (-9 , -3)

Step-by-step explanation:

let p2 be (a , b)

given :

p1(-1 , 7) = (x1 , y1)

p2(a , b) = (x2 , y2)

using midpoint formula:

midpoint = (x1 + x2/2 , y1 + y2/2)

(-5 , 2) = (-1 + a/2 , 7 + b/2)

Now , compare corresponding elements

-5 = -1 + a/2

-5*2 = -1 + a

-10 = -1 + a

-10 + 1 = a

-9 = a

2 = 7 + b/2

2*2 = 7 + b

4 = 7 + b

4 - 7 = b

-3 = b

therefore p2 = (-9 , -3)

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2

45

step-by-step explanation: