A student wants to check six websites. Four of the websites are social and two are school-related. After checking just two sites, she has to leave for school. What is the approximate probability that she checked a social website first, then a school-related website?

0.042
0.267
0.533
0.667

0.042 is the correct answer

The approximate probability that she checked a social website first and then a school-related website is 0.267.

Step-by-step explanation:

Given that a student wants to check six websites, and four of the websites are social and two are school-related, and after checking just two sites, she has to leave for school, to determine what is the approximate probability that she checked a social website first, then a school-related website, the following calculation should be performed:

4/6 x 2/5 = X

0.26666666 = X

Therefore, the approximate probability that she checked a social website first and then a school-related website is 0.267.

B. 0.267    The guy above me is correct!

Step-by-step explanation:

Edge 2021  Got a 100% on the test

la parábola es el lugar

geométrico en el cual los puntos tienen una distancia idéntica, equidistantes,

de un punto denominado foco, f, y una recta denominada directriz

el radio vector de una

parábola es el segmento que existe entre un punto cualquiera y el foco.

por la ecuación se observa

que la parábola abre hacia la derecha, por lo cual podemos usar las siguientes fórmulas

la ecuación ordinaria de la

parábola es y^2 = 4px, donde p es la longitud desde el vértice de la parábola al

foco.

la fórmula de la directriz

es x + p = 0

resolviendo:

y^2-9x = 0

y^2 = 9x

4p = 9, entonces p = 9/4

entonces el foco tendrá la

coordenada f(9/4,0)

la directriz vendrá

expresada por

x + p = 0

x = -p

x = -9/4

el problema indica que la

ordenada es igual a 6, entonces

(6)^2=9x

x = 36/9

x = 4

entonces el punto al cual

hay que obtener la distancia será p(4,6)

calculando se tendrá: pf = 

pf = 6,25 u

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step-by-step explanation: