The LCM of two numbers is 48. The number one in the ratio 2:3. Then Sum of the numbers is: a) 16
b) 14
c) 32
d)28​

40

Step-by-step explanation:

Let the numbers be 2x and 3x

Then their L.C.M. = 6x

BUT also their LCM=48

6x=48

x=48/6

x=8

So,

First number=2x=2x8=16

Second number=3x=3x8=24

The numbers are 16 and 24.

Hence required sum =(16+24)=40

So none of the options are correct

2

step-by-step explanation:

a is the right answer