Suppose that 60 batteries are shipped to an auto parts store, and that 5 of those are defective. A fleet manager then buys 6 of the batteries from the store. In how many ways can at least 4 defective batteries be included in the purchase

In 8910 ways can at least 4 defective batteries be included in the purchase

Step-by-step explanation:

The order in which the batteries are there is not important, which means that the combinations formula is used to solve this question.

Combinations formula:

is the number of different combinations of x objects from a set of n elements, given by the following formula.

In this question:

4 defective:

4 defective from a set of 5 and 2 non-defective from a set of 60 - 5 = 55. So

5 defective:

5 defective from a set of 5 and 1 non-defective from a set of 60 - 5 = 55. So

In how many ways can at least 4 defective batteries be included in the purchase?

In 8910 ways can at least 4 defective batteries be included in the purchase

45

step-by-step explanation:

about 0.75 hours

step-by-step explanation: