Yoko, trey, and alan have a total of $115 in their wallets. Alan has 3 times what Yoko has. Yoko has $5 less than Trey. How much do they have in their wallets?

Yoko has $22, Alan has $66, and Trey has $27

Step-by-step explanation:

Let x represent how much money Yoko has.

Alan has 3 times as much as Yoko, so his amount can be represented by 3x.

Trey has $5 more than Yoko, so his amount can be represented by x + 5.

Add these together and set them equal to 115. Then, solve for x:

(x) + (3x) + (x + 5) = 115

5x + 5 = 115

5x = 110

x = 22

So, Yoko has $22.

Alan has 3 times as much, so multiply this by 3:

22(3) = 66

Alan has $66.

Yoko has $5 less than Trey, so add 5 to this:

22 + 5 = 27

Trey has $27.

Yoko has $22, Alan has $66, and Trey has $27

the correct answer is 5 6 and 7

well what did you do it matters what you did : )

step-by-step explanation: