Find the first two expressions in the sequence _, _, 4x+5, 5x+7, 6x+9, 7x+11, 8x+13...

First term: 2x+1

Second term: 3x+3

Step-by-step explanation:

The coefficient of x is going up by 1 time each time while the constant term is going up by 2.

We are looking at these two questions basically:

1) What are the first two terms in?

_,_,4,5,6,7,8

2) What are the first two terms in?

_,_,5,7,9,11,13

Answers:

1) Since the sequence is going up by 1 reading left to right, then right to left it's going down by 1.

So before 4, we have 3.

Before 3, we have 2.

The sequence for the coefficient of x is 2,3,4,5,6,7,8

2) Since the sequence is going up by 2 from left to right, then it's going down by 2 reading right to left.

So before 5, we have 3.

Before 3, we have 1.

The sequence for the constant term is 1,3,5,7,9,11,13.

So first two terms of the sequence in ascending order according to the sequence is:

2x+1

3x+3

the answer for this question is 38

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0