Find the area of the surface generated when the given curve is revolved about the given axis. 5x^1/3

Step-by-step explanation:

The curve x = f(y)

The area of the surface around the y-axis from y = a → y = b is:

From the given curve:

; assuming the region bounded by the curve is 0 ≤ y ≤ 1

So;

5x = y³

The differential of the above equation Is:

Now, we have the area of the surface produced around the curve through the y axis from the region y = 0 to y = 1

∴

Let make

It implies that:

when y = 0 ;

u = 5

when y = 1;

∴

The equation can be written as:

location: point 0

step-by-step explanation:

well, -8 to 10 on a number line is 18 spaces.

1/9 of 18 is 2.

so, 4/9 of 18 must be 8.

8 spaces from -8 (a) is 0.

so, 4/9 of the way from -8 to 10 is 0!