For the Transformation T write the T-1 T: (x, y) = (x + 4, y + 3)
Т-1 (x, y) -
(x+3, y + 2)
(x-4, y-3)
(x+, y + 3)

(T - 1)(x, y) = (x - 4, y - 3)

Step-by-step explanation:

For a given transformation:

T(x, y) = (x', y')

the inverse transformation is defined by:

(T - 1)(x', y') = (x, y)

So, if our transformation is:

T(x, y) = (x + 4, y + 3)

Then for the inverse transformation, we should have:

(T - 1)(x + 4, y + 3) = (x, y)

So the inverse transformation reduces the x-value by 4, and reduces the y-value by 3.

Writing the inverse transformation for a generic (x, y) point, we get:

(T - 1)(x, y) = (x - 4, y - 3)

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.