solution - 12. The digit in the tens place of a two-digit number is three times that in the units place. If the digits are reversed, the new number will be 36 less than the original number. Find the original number. Check your solution.​

62

Step-by-step explanation:

t=digit in the tens place

u=digit in the units place

t=3*u

original number=t*10+u

number with reversed digits=u*10+t

u*10+t=t*10+u-36

u*10+(3*u)=(3*u)*10+u-36

10u+3u-30u-u=-36

-18u=-36

u=2

t=3*u=6

Original number = 62

Check the solution:

6=3*2 ok

26=62-36 ok

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation:

69.64%

step-by-step explanation: