Find the surface area of a water tower that is 40 feet tall and 20 feet across the base. _ square feet​

the surface area is 3140 square feet

Step-by-step explanation:

The computation of the surface area is given below:

Given that

Diameter = 20 feet

radius =  20 ÷ 2 = 10 feet

Surface area =  

= 2 × 3.14 × (10)^2 + 2 × 3.14 × 10 × 40

= 6.28  × 100  + 6.28  × 400

= 628 + 25.12  × 100

= 628+ 2512

= 3140 square feet

hence, the surface area is 3140 square feet

f(x) is going down by 4

step-by-step explanation:

(its either that or its going left by 4)