Find the lateral area of this square based pyramid. 10in 5 in [ ? ]in?​

Step-by-step explanation:

Lateral area, Al = a√(a² + 4h²)

Where,

a = base edge = 5 in

h = height = 10 in

Lateral area, Al = a√(a² + 4h²)

= 5√(5² + 4*10²)

= 5√(25 + 4*100)

= 5√(25 + 400)

= 5√425

= 5 * 20.615528128088

= 103.07764064044

Approximately,

Lateral area = 103.08 in²

first one is a: renaming a fraction. second one is c: de-c

step-by-step explanation:

my explanation is that these were the answers on edg : )