A line is parallel to y = 3x + 5 and intersects the point (-2 , 6). What is the equation of this parallel line?

y = 3x + 12

Step-by-step explanation:

Slope of y = 3x + 5 is 3

Line parallel will have same slope 3

Line intersects point at (-2, 6)

Replace into y = mx + b to find

6 = 3(-2) + b

6 = -6 + b

12 = b

Equation of line:

y = 3x + 12

y = 3x + 12

Step-by-step explanation:

Lines parallel to each other will have the same slope but different y-intercepts. This means that the equation of this parallel line has a slope of 3.

y = 3x + b

Now we need to find the y-intercept by plugging in the point (-2, 6) into the equation. (Replace x with -2 and y with 6.) Then we solve it.

y = 3x + b

6 = 3(-2) + b

6 = -6 + b

+6 +6

12 = b

The y- intercept is 12. So the equation of the parallel line is y = 3x + 12

  21.3

step-by-step explanation:

multiplying the given equation by c/sin(25°), we get

  c = 9/sin(25°) ≈ 21.2958 ≈ 21.3

we assume "c" is the length of ab, the side opposite angle c in triangle abc.

-362

step-by-step explanation:

(12)(4)+2(12)-34(12)+2(12)-3

  \/         \/         \/         \/

  48 +   24 -   408 + 24 - 3

      \   /               \   /

          72     -     432 - 3 = -363