Help 0-0-0-0-0-0-0-0-0-0-0-0-0-0

(12,0)

Step-by-step explanation:

So whenever you are asked for an "intercept" it is the point where a line crosses the axis. The x intercept is where the line crosses at the x axis (horizontal line on the graph) and the y intercept is where the y axis crosses (vertical axis).

So this question is really asking where is the point when y = 0

The x values in the chart are 5 apart-- 22 +5 = 27, 27+ 5 = 32

The y values are 18 apart --> 36 + 18 = 54, 54+ 18 = 72

Make a little chart where y = 0 (this is where the x crosses) and you can see

there is a point at (17, 18) and then (12, 0) and that point is the x intercept.

(12, 0)

Step-by-step explanation:

the x-intercept is the point, where y=0.

so, the second coordinate is therefore 0, no matter what.

now, at what x is that ?

let's find the line function.

a line is

y = a×x + b

let's use the first point (22, 36)

36 = a×22 + b

a = (36 - b)/22

let's use the second point (27, 54)

54 = a×27 + b

now we use the first expression describing a in terms of b and insert that into the second expression.

54 = 27×(36 - b)/22 + b

54×22 = 27×(36 - b) + 22b = 972 - 27b + 22b

1188 = 972 - 5b

216 = -5b

b = -43.2

=>

a = (36 - -43.2)/22 = (36 + 43.2)/22 =79.2/22 = 3.6

our line is

y = 3.6x - 43.2

so, now back to the question, at what x is y=0 ?

0 = 3.6x - 43.2

3.6x = 43.2

x = 12

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hope this !

sorry i need the points

step-by-step explanation:

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