Find mZHFG if mZEFG = 2x + 52, mZEFH = 21°, and mZHFG = 1 + 31

m<HFG = 31

Step-by-step explanation:

We can say that m<EFH + m<HFG = m<EFG because of angle addition postulate. Now, we can substitute the values of the angles in.

21 + x + 31 = 2x + 52

x + 52 = 2x + 52

x = 0

Now, we substitute x into the expression of m<HFG:

m<HFG = x + 31

m<HFG = 0 + 31

m<HFG = 31

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

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