The length of a rectangle is eight more than double the width. If the perimeter is 130 inches, find the dimensions.

The length is 46 inches and the width is 19 inches

Step-by-step explanation:

Let w represent the width.

The length of the rectangle can be represented by 2w + 8, since it is eight more than double the width.

Use the perimeter formula, p = 2l + 2w. Plug in 130 as the perimeter and 2w + 8 as l, then solve for w:

p = 2l + 2w

130 = 2(2w + 8) + 2w

130 = 4w + 16 + 2w

130 = 6w + 16

114 = 6w

19 = w

So, the width is 19 inches. Plug in 19 as w into 2w + 8 to find the length:

2w + 8

2(19) + 8

38 + 8

= 46

The length is 46 inches and the width is 19 inches

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

i cant answer this, theres no table. sorry man

step-by-step explanation: