Which compound equalities have x = 2 as a solution? Check all that apply O 4 < 5x - 1 <10
O4 < 5x - 3 < 10
04 < 5x - 7 < 10
04 < 2x + 1 < 10
04 < 2x + 3 < 10
O 4 < 2x + 6 < 10

Step-by-step explanation:

Required

Whose solution is

Add 1 to both parts

Divide through by 5

Substitute 2 for x

--- this is true

Add 3 to both parts

Divide by 5

Substitute 2 for x

--- this is true

Add 7 to both parts

Divide by 5

Substitute 2 for x

--- this is false because 2.4 > 2

Subtract 1 from all parts

Divide by 2

Substitute 2 for x

--- this is true

Subtract 3 from all parts

Divide by 2

Substitute 2 for x

 ----- this is true

Subtract 6 from all parts

Divide by 2

Substitute 2 for x

--- this is false because 2 = 2; not 2 < 2

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

sorry i just need to anwers this to get points

step-by-step explanation: