The capacity of a CD-ROM is 800 MB (800 x 20 raised to 20 bytes). It stores information along a spiral track. If each byte uses a space of 9 microns, what is the length of the complete track in m? (Hint: 1 micron= 10 Raised to-6m)

The length of the complete track=

Step-by-step explanation:

We are given that

Capacity of CD-ROM=800MB=

1 byte=9 microns

We have to find the  length of the complete track in m.

We change MB into  micron

=

Now, we change micron into m

=

Hence, the length of the complete track=

t = 3

step-by-step explanation:

put t = 3 in this expression :

(3²-1)(3²-2)(3² - 3)(3² - 4) = 8×7×6×5 = 56×30 = 1680