What are the solutions of the equation (x + 2)^2+ 12(x + 2)-14=0? Use u substitution and the quadratic formula to solve

Step-by-step explanation:

Obviously, we are letting u = x + 2. So what we have when we rewrite using this substitution is

and we plug that into the quadratic formula with

a = 1, b = 12, c = -14:

which can be simplified to

and a bit more to

and a tiny bit more to

and finally to

and plug back in for u:

x + 2 = -6 ± 5√2 and then subtract the 2 to get

x = -8 ± 5√2

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation: