Suppose a basketball team had a season of games with the following characteristics: Of all the games, 60% were at-home games. Denote this by H (the remaining were away games).
Of all the games, 25% were wins. Denote this by W (the remaining were losses).
Of all the games, 20% were at-home wins.
Of the at-home games, what proportion of games were wins? (Note: Some answers are rounded to two decimal places.)
a. 0.12
b. 0.15
c. 0.20
d. 0.33
e. 0.42

Hello Sir/ Mam

YOUR REQUIRED ANSWER IS 18.6%

Variables defined in the question:

H - Home - Games

W - Winning Games

Now, given:

P(H0.62 PW)0.22

P(W\mid H)=0.30

Required : Of all the games, percentage of games that were at home wins.

Hence, required :

P(W\cap H)

Now, we know that:

P(W\mid H)=\frac{P(W\cap H)}{P(H)}

0.3=\frac{P(W\cap H)}{0.62}

Hence,

P(W\cap H)=0.3*0.62=0.186=18.6\%

I hope this solves your doubt.

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Step-by-step explanation:

in mathematics, a function is a relationship between two variables such that the value of one of the variables, called the dependent variable, is determined by the value of the other variable, called the independent variable. there is a specific term we use to describe the set of independent variables of a function.

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