On a coordinate plane, line P Q goes through (negative 6, 4) and (4, negative 4). Point R is at (4, 2). Which point is on the line that passes through point R and is perpendicular to line PQ?

(–6, 10)
(–4, –8)
(0, –1)
(2, 4)

answer: 0

step-by-step explanation: the positive, like 5, + its opposite, like -5 would be 0

5+(-5)=0, or 5-5=0

i'm not really sure how to answer that

step-by-step explanation:

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0

i think its 7.6

if so your welcome