Let the mean of the population be 38 instances of from 6"-9" hatchings per nest, and let the standard deviation of the mean be 3. What sample would have a confidence level of 95% or a 2 5% margin of error?​

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3

the eight graders whould be the answer

step-by-step explanation: could you give me 5 stars

5.7622

step-by-step explanation:

the ten thousandths place is the 2. you round it up if, that number in whatever place is 5 or higher.